WebAlgebra Find the Domain and Range y = log base 2 of x Step 1 Setthe argumentin greater than to find where the expressionis defined. Step 2 The domainis all values of that make … WebSolution: Given function, f (x) = sin−1 [log2(2x)] Since, −1 ≤ sinx ≤ −1. ⇒ −1 ≤ log2 (2x) ≤ 1. ⇒ 2−1 ≤ x/2 ≤ 21. ⇒ 20 ≤ x ≤ 22. ⇒ 1 ≤ x ≤ 4. Required domain is x ∈ [1,4].
The domain of fx=sin 1[log2x/2] is
Web2 Answers Sorted by: 1 The range of sin ( x − 3), where x is any real number is [-1, 1]. The domain of log p is p > 0, since log is not defined for real numbers less than or equal to 0. So the range on log ( sin ( x − 3)) is (-infinity, log (1)) EDIT: based on question edit domain has to be where 0 < sin ( x − 3) ≤ 1 and where ( 16 − x 2) ≥ 0 WebAnswer: Since the logarithmic function is always positive for x>0 .From this you can conclude that the domain of sin^-1 is positive integers. Now the range of log will be domain of sin^-1 x .Range of log will be (0,infinity ).But we know that the domain of sin^-1 can be from -1,1 . Hence in your... michelle owenby tdec
The domain of the function f(x)=sin−1[log2 (x/2)] is (where [.].
Web>> The domain of f (x) = sin^-1 {log3 (x^2/3 Question The domain of f(x)=sin −1{log 3( 3x 2)} is A (−∞,3] B [3,∞) C [−3,−1]∪[1,3] D (−9,−1)∪(1,9) Medium Solution Verified by Toppr Correct option is C) sin −1x is defined if x∈[−1,1] ⇒−1≤log 3 3x 2≤1 ⇒ 31≤ 3x 2≤3 1≤x 2≤9 ⇒x∈[−1,−3]∪[1,3] ∴x∈[−3,−1]∪[1,3] Was this answer helpful? 0 0 Similar questions WebThe domain of sin −1[log 2(x 2/2)] is A [2,1] B [1,2] C [−2,−1]∪[1,2] D [−2,0] Medium Solution Verified by Toppr Correct option is C) sin −1(x)domain:x∈[−1,1] ∴ domain of sin −1[log 2 2x 2] ∴log 2 2x 2∈[−1,1] −1≤log 2 2x 2≤1 and 21≤ 2x 2≤2 1≤x 2≤4 For x 2≥1 x∈[−∞,−1]∪[1,∞] ........... (i) For x 2≤4 x∈[−2,2] ................. (ii) WebQ: log2 Find the domain of the function f(x) = sin 2 A: Recall: If logbx=y is equivalent to by=x . Domain of inverse function of sine is -1,1. michelle owen sky sports legs